4m^2+4=288

Solution for 4m^2+4=288 equation:

4m^2+4=288

We move all terms to the left:

4m^2+4-(288)=0

We add all the numbers together, and all the variables

4m^2-284=0

a = 4; b = 0; c = -284;
Δ = b2-4ac
Δ = 02-4·4·(-284)
Δ = 4544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4544}=\sqrt{64*71}=\sqrt{64}*\sqrt{71}=8\sqrt{71}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{71}}{2*4}=\frac{0-8\sqrt{71}}{8}
=-\frac{8\sqrt{71}}{8}
=-\sqrt{71}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{71}}{2*4}=\frac{0+8\sqrt{71}}{8}
=\frac{8\sqrt{71}}{8}
=\sqrt{71}
$